Ramanujanova zveza med osnovnimi konstantami Objavljeno 15. marca, 2017 , AndrejJ Shrinivasa je našel tole:
![\[{\sqrt{5+\sqrt{5}\over 2}-\phi} = \cfrac{e^{-\frac{2\pi}{5}}}{1 + \cfrac{e^{-2\pi}}{1 + \cfrac{e^{-4\pi}}{1 + \cfrac{e^{-6\pi}} {1 + \cfrac{e^{-8\pi}} {1+\ddots}}}}}\]](https://vincenc.petruna.com/wp-content/ql-cache/quicklatex.com-efe784fded7b7651f4ad7186908982fa_l3.png "Rendered by QuickLaTeX.com")
